Where Minaur advanced to the fourth round of the tournament in Cincinnati
Australian tennis player Alex de Minaur defeated Britain’s Arthur Fery in the third round of the Cincinnati Open in the U.S. state of Ohio and advanced to the round of 16. The fifth seed won with a score of 7-5, 7-6 (7-3), according to ABC News Australia.
The match lasted 2 hours and 22 minutes and was interrupted three times due to rain. Early in the match, de Minaur was forced to save three break points on his serve. In the 11th game of the first set, the Australian broke serve and then held his own serve without dropping a point.
After play resumed, de Minaur broke his opponent’s serve twice and took a 5-1 lead in the second set. However, Fery evened the score at 5-5, and the set was decided by a tiebreak, which the Australian won 7-3.
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In the next round, de Minaur will face either the ninth-seeded Czech, Jiří Lehečka, or the 21st-seeded Frenchman, Arthur Fiss. The Australian last reached the fourth round in Cincinnati in 2019.
De Minaur said he was pleased with how he found his way to victory, although the end of the match proved tougher than he had expected. According to him, he played a very good match until the last rain delay, and after that, he had to focus on every point.
Another Australian player, Rinki Hijikata, failed to advance to the round of 16: he lost to 14th-seeded Czech Jakub Menšík 3-6, 4-6.
